6x^(2/3)-23x^(1/3)-4=0

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Solution for 6x^(2/3)-23x^(1/3)-4=0 equation: 


x in (-oo:+oo)

6*x^(2/3)-(23*x^(1/3))-4 = 0

6*x^(2/3)-23*x^(1/3)-4 = 0

t_1 = x^(1/3)

6*t_1^2-23*t_1^1-4 = 0

6*t_1^2-23*t_1-4 = 0

DELTA = (-23)^2-(-4*4*6)

DELTA = 625

DELTA > 0

t_1 = (625^(1/2)+23)/(2*6) or t_1 = (23-625^(1/2))/(2*6)

t_1 = 4 or t_1 = -1/6

t_1 = -1/6

x^(1/3)+1/6 = 0

1*x^(1/3) = -1/6 // : 1

x^(1/3) = -1/6

( -1/6 < 0 i 1/3 in (0:1) ) => x naleu017Cy do O

t_1 = 4

x^(1/3)-4 = 0

1*x^(1/3) = 4 // : 1

x^(1/3) = 4

x^(1/3) = 4 // ^ 3

x = 64

x = 64

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